Additional Reading ... C Programming: Problem 16 - Build the stack (Queue) Programming C: Last 15 -

Really when this article weigh yourself do not know its title should write out why ... "Check the number you enter there is some"@@Slightly funny because some have called then check what to do, or is "Check the number of C" - well not quite ready for the purposes of this article. And finally decided to put as above for the purpose of entering into by scanf will know immediately that there must be a number or not.
The program will perform the following request you to enter an integer (int), if you enter the wrong number (whether any string format "12dabc", "abc123" and even made some 12.3) they are caught you in again.
#include <stdio.h> #include <stdlib.h> int clean_stdin () {while (getchar ()! = 'n') {} return 1; } Int main (void) {int input; char c; do {printf ("Enter an integer:"); } While (((scanf ("% d% c", & input, & c)! = 2 || c! = 'N') && clean_stdin ())); printf ("done, number is% d", input); return 0; }
scanf ("% d% c", & input, & c) This will allow us to enter into an integer and a character that immediately follows an integer, and it returns an integer - number turn it receives (scan) is in accordance with the format in the format string. - If you enter abc, the function returns a value of 0 because it can not read any suitable value. karenmillen - If you enter 123 and press Enter, the return value is 2 2 value that is acceptable format, and enter 123 for% d for% c. - If you enter 123abc and press Enter, the return value is 2 2 value that is acceptable format, and 123 for% d% c for a character.
scanf ("% d% c", & input, & c)! = 2 || c! = 'n' It ensures that the amount of data that scanf scans are not as 2 or letters received not enter. Put this condition in the while to the machine can perform properly karenmillen if you do not have to enter the right number and then enter it will repeat.
(Scanf ("% d% c", & input, & c)! = 2 || c! = 'N') && clean_stdin () function clean_stdin () is the function always returns a value of 1 (which is always true) it's Mansion the deletion of the buffer (stdin) by reading the entire character left in the buffer (the character that scanf can not read the formatting of it) until the reader to enter characters. The conditions put it in a while loop to wipe cache every time you enter the wrong to re-enter service next time.
Posted in LT C - C ++ | Tags: catch enter in C, check number in C, test string is zero in C, check the input string karenmillen can be zero, check the entered numbers in C, check enter the correct number
Additional Reading ... C Programming: Problem 16 - Build the stack (Queue) Programming C: Last 15 - Installing stack (Stack) C Programming: Problem 14 - doubly karenmillen linked list C Programming: Last 13 - List installed applications linked by pointers Programming C: Unit 12 - List of links set in array
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With me, your idea totally wrong then, of your code so you do not check the exception and crash occ

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With me, your idea totally wrong then, of your code so you do not check the exception and crash occurs offline. Post your problem with him have stated as follows: B1: Enter 1 string str; B2: Input 1 (expect to be in the string favoptic str) that you want to replace; B3: Enter the words you use one instead favoptic of the above; favoptic B4: Handling and output to screen sequences favoptic been replaced; String in C is actually an array of characters favoptic alone; You can use functions such as strcmp, strlen, ... to handle. But if you can use C ++, use string and 1 stl algorithms, simple handling safety.
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5. Write all the programs into four integers. Find and print the largest number. int main () {int a

4. Write a program all in positive integers x. in the announcement of an even or odd number. int main () {int x; printf ("Enter in x:"); scanf ("% d", & x); if (x% 2 == 0) printf ("x is the number of chan"); else printf ("x is odd"); return lapolicegear 0; }
5. Write all the programs into four integers. Find and print the largest number. int main () {int a, b, c, d, max1, MAX2, max; printf lapolicegear ("Click 4 integers a, b, c, d: \ n"); scanf ("% d% d% d% d", lapolicegear & a, & b, & c, & d); if (a> b) max1 = a; else max1 = b; if (c> d) MAX2 = c; else MAX2 = d; if (max1> MAX2) max = max1; max = MAX2 else; printf lapolicegear ("the largest positive integer:% d", max); return 0; }
6. Write a program to solve all quadratic lapolicegear equation 2 + bx + c = AX2 0, with a, b, c input from the keyboard. int main () {float a, b, c, Delta, x1, x2; printf ("Enter in the three variables lapolicegear a, b, c: \ n"); scanf ("% d% d% d", & a, & b, & c); Delta = (b * b) - (4 * a * c); if (Delta <0) {printf ("equation lapolicegear vo nghiem"); return 0; } If (Delta == 0) x1 = x2 = -b / (2 * a); else {x1 = (- b-sqrt (Delta)) / (2 * a); x2 = (- b + sqrt (Delta)) / (2 * a); } Printf ("x1 =%. 2f \ n", x1); printf ("x2 =%. 2f", x2); return 0; }
Last 7. Write a program in hours, minutes, seconds (hh: mm: ss). Plus the number of seconds in and print out the results in the form hh: mm: ss int main () {int hh, mm, ss, t; printf ("Enter in hours, minutes, seconds: \ n"); scanf ("% d% d% d", & hh, and mm, and ss); printf ("Click Shine added: \ n"); scanf ("% d", & t); if (ss + t <60) {ss = ss + t; } Else {ss = (ss + t) -60; mm mm + = 1; } If (mm> = 60) {mm = mm - 60; hh hh = +1; } Printf ("\ ngio: minutes: seconds:% .2d:%. 2d:%. 2d", hh, mm, ss); return 0; }
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Use string in C string in C is very much related to the cursor. When you're used to using the cursor, you can transport chain used to handle more efficiently. A string in C is simply an array of characters. The following line declares an array that can hold a string music boxes of up to 99 characters.
Str array of characters stored as follows: str [0] is the first character of the array, str [1] is the second character, and so on. But why a 100-element array to hold up to 99 characters. Because C uses null-terminated strings, that is the end of a string is marked by characters with ASCII code 0 (the null character), which is represented in C '' music boxes
In C, as already said, we can not simply assign one array to another array, where each element to copy. Library strcpy string containing allows you to do this. The following code shows how to use strcpy function to copy the string: #include <string.h> void main () {char s1 [100], s2 [100]; strcpy (s1, "hello"); / * Copy "hello" into s1 * / strcpy (s2, s1); / * Copy s1 into s2 * /}
Strcpy function is used when you need to initialize a chuoi.Trong C, you must use the strcmp function in the string library, which compares two strings and returns an integer that indicates the result of the comparison. The result music boxes is 0 means that two strings are equal, a negative value means that s1 s2. #include <string.h> void main () {char s1 [100], s2 [100]; gets (s1); gets (s2); if (strcmp (s1, s2) == 0) printf ("equal \ n"); else if (strcmp (s1, s2) <0) printf ("s1 is less than s2 \ n"); else printf ("s1 is greater than s2 \ n"); }
Some other common functions in the string library strlen, which returns the length of the string; strcat chain connecting the two. You can refer to the help section of Turbo C.Ban need to build some string handling functions for himself. Let's start with rewriting strlen. Here is a coding style you already familiar with Pascal: int strlen (char s []) {int x; x = 0; while (s [x]! = '') x = x + 1; return (x); }
Most C programmers do not like this approach because it seems inefficient. Instead, music boxes they often use an approach based on a pointer: int strlen (char * s) {int x = 0; while (* s! = '') {x ++; s ++; } Return (x); }
However, the actual running and compare three programs music boxes above, you will see their time performing the same or very small difference. That means, music boxes you should write code in any way you see most understandable code. Pointers generally make programs run faster, but strlen does not belong in that case.
Note the <= because this code to copy the characters ''. Another thing that this code is very inefficient, because strlen gets called every time you repeat loop. To solve this problem, you can use the following code: strcpy (char s1 [], char s2 []) {int x, len; len = strlen (s2); for (x = 0; x <= len; x ++) s1 [x] = s2 [x]; }
Even you can say while (* s1 ++ = * s2 ++); This time, when the trial, you will see the first version to run very slowly, while the third edition and fourth faster than the second version. In this case, the cursor really effective.
Use the cursor to create chains sometimes markedly effective rate. For example, suppose you want to remove leading blanks in a string. In C, you often have to use the delete function as follows: #include <stdio.h> #include <string.h> void main () {char s [100], * p; gets (s); p = s; while (* p == '') p ++; printf ("% s \ n", p); }
Two code even give the same results, but their behavior is completely different. In paragraph 2, you can not write s = "hello" ;. To understand the difference, music boxes you need to know the operation of the constant table (string constant table) in C.
When the program is executed, the compiler creates an object file containing machine code and a string table containing all constants music boxes declared in the program. music boxes In paragraph 1, the statement s = "hello"; determined that s only to the address of the string hello in the constant table. Because this sequence is located in the constant table, and is part of the executable code, so you can not change it. You can only use it according to the type of read-only (read-only).
This code compiles, but it generates an error "segmentation fault" right in line free. Because malloc to create a block of 100 bytes of memory and point s on it, but the line s = "hello"; s points to a string in table string constants, and memory blocks 100 bytes skipped. Thus free fails because it can not liberate a memory block in an executable region.
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If this is your first visit C Vietnamese community forum, please learn the rules involved, j mendel

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Read his books, they have said is a string of characters char array, and so on, but also found hims

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Read his books, they have said is a string of characters char array, and so on, but also found himself alone with questions after his code [CODE] #include <iostream> using std :: cout; using std :: cin; using std :: endl; int main () {int array [5] = {1,2,3,4,5}; lowrys farm int * PTR1 = array; cout << endl << PTR1; cout << endl << * PTR1; PTR1 ++; cout << endl << * PTR1; char str [] = "Teach Yourself Programming"; char * str = ptr2; cout << endl << * ptr2; ptr2 ++; cout << endl << * ptr2; char ** ptr3 = & ptr2; cout << endl << ptr3; (* Ptr3) ++; cout << lowrys farm endl << * ptr3; system ("pause"); return 0; } People ask themselves why the cursor in ptr2 chain, it does not address such as in PTR1 on the array, whereas the value in using * ptr2 it still printed lowrys farm characters (like in the array ).
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Is 1-dimensional array of elements of type char as letters, numbers, and any special characters suc

Is 1-dimensional array of elements of type char as letters, numbers, and any special characters such as +, -, *, /, $, # ... Write in quotes, eg "I like C ++ "-According to the convention, a string willbe terminated by the null character ('\ 0': letters turong). -Xau Is a cursor (pointer) points to the first character of the string (like the array) Example: string s = "Infoworld"; stored as follows:
In this pointer points to sign tudau s first 'I' Ends with nul lnhu so very different from other languages. For example, in Pascal, each string consists of an array of characters and length byte string length. This structure helps ease Pascal string length returned upon request. Meanwhile, Pascal simply returns the byte length, while C to count until it encounters the character '\ 0'. This is why C Pascal slower in some certain situations 1.Gan value for the string (string assignment) An array of characters: char color [] = "blue"; Char * pointer char * colorPtr = "blue"; colorPtr Pointer pointing to a string literal b in "blue" snorg tees ("blue" otrong constant table) Initialization string as array: snorg tees char color [] = {'b', 'l', 'u', 'e' , '\ 0'}; snorg tees Need to remind you that many constants assigned as the use of quotation marks (") is only valid when initializing the array, ie at the array declaration. The expressions in the following program is not valid: snorg tees mystring = "Hello"; mystring [] = "Hello"; mystring = {'H', 'e', 'l', snorg tees 'l', 'o', snorg tees '\ 0'}; we just can "assign" more v loud constant for an array initialization it. The reason snorg tees is motthao work assignment (=) can not be clarified that an array can only get one element of it. At the time of initializing an array special case, because it's not really an assignation, although it uses sign (=). However, C ++ allows us to assign two static arrays of the same size as follows: chara [] = "Hello", b [6]; // null character hello and a total of 6 characters // declared as static on the two arrays of the same size b = a; Assignments equivalent program fragment: int i = 0; while (a [i] <= 6) b [i] = a [i ++]; Set n the first character of the string s with the symbol that c is 1 in 2 following function: voidstrnset (chars [], charc, intn): void memset (char * Des, INTC, size_tn); 2. What two string constants Try the following program fragment: char * s = "hello"; cout << snorg tees s; and: chars [100]; snorg tees strcpy (s, "hello"); cout << s; Two code even give the same results, but their behavior is completely different. In paragraph 2, you can not write s = "hello" ;. To understand the difference, you need to know the operation of the constant table (string constant table) in C. When the program is executed, the compiler creates an object file containing machine code and a table containing all the string constants declared in the program. In paragraph 1, the statement s = "hello"; s only to determine that the address of the string hello in the constant snorg tees table. Because this sequence is located in the constant table, and is part of the executable code, so you can not change it. You can only use it according to the type of read-only (read-only) snorg tees .To illustrate, you can add commands strcpy (s, "modify"); assigned to the following command in example 1, the compiler will write to the constant error. In paragraph 2, the string hello also exists in the constant table, so you can copy it to the array of characters named s. Because s is not a pointer, the statement s = "hello"; snorg tees will not work. Will be addressed by the pointer. 3. read sequence Read data for character array: char word [20]; cin >> snorg tees word; -dOc String does not accept spaces. -Xau May exceed the size of the array. cin >> setw (20) >> word; // Read 19 characters (one reserved for '\ 0') Read the string with blanks using one of the following syntax: gets (array); // in stdio.h, is not recommended to use cin .get (array); cin .get (array, size); cin .getline (array, delimiter = '\ n'); // Default is the delimiter character '\ n' bone cin .getline snorg tees dong (array, size, delimiter = '\ n'); -Save Input into the array array to the occurrence of two cases + data size reaches the size -1 + delimiter character snorg tees is entered Note: delimiter = '\ n' th idau = Latham default in C ++ , ie without this parameter, the compiler will understand that to default Example: charsentence [80]; cin.getline (sentence, 80); // Default delimiter solution for the getline function or get one absolutely can combine with operator >> like this: cout << snorg tees "Enter the name, age, occupation" << endl; //cin.ignore (); cin .getline (name) >> >> job age; If a program crashes or ends abnormally when working with strings usually because some characters are still in the buffer zone. The result is a program that seems to end sooner than expected. The function fflush () or cin.ignore () will solve this problem. It will clean up all buffers and what is in the buffer zone outside (in the example above, snorg tees it does not really need

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Code: #include <stdio.h> #include <conio.h> #include <stdlib.h> #include <string.h> int main () {char * str = (char *) malloc (sizeof (char)) ; printf ("Enter the string:"); gets (str); DoDaiChuoi int = strlen (str); Rub cavity in the middle of the page // int i, j; for (i = 0; i <= DoDaiChuoi - 1; i ++) {while ((str [i] == '' || str [i] == '\ t') && (str [i + 1] == '' || str [i + 1] == '\ t')) {for (j = i + 1; j <= DoDaiChuoi; j ++) str [j] = str [j + 1]; }} Printf ("\ n \ n"); // Remove the first whitespace parasuco string. if (str [0] == '') {for (i = 0; i <DoDaiChuoi; i ++) str [i] = str [i + 1]; } // Remove whitespace string parasuco end if (str [DoDaiChuoi] == '') str [DoDaiChuoi] = '\ 0'; printf ("bad after treatment: \ n"); printf ("% s", str); getch (); return 0; }
{
}
return 0;
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char * strlwr (char * s)

The constant string is placed in quotation marks "".
In this declaration, the memory will take two bytes to store the address of the pointer is pointing to Ten, yet provides a place to store data. Want to have a place to store the data, we must call to malloc () or calloc () in "alloc.h", then assigned to the variable data.
The syntax is:
char * strlwr (char * s)
The function strstr () is used to find the first occurrence of the string s2 in the string s1.
Results returned similar results returned by the function strcmp ()
Posted by German Czech Dance at 15:32
Research on the data type string pantofi senzationali Ø Contents: 1. Declare string 2. Learn the handler Chuo ...

Lesson 4: Write a program manolo in the sphere radius, calculate manolo and print out the area, th

Lesson 3: Write a program to read two integers and print out the result of the (+), subtraction (-), multiplication (*) division (/). Comment manolo 2 integer division results. int main () {int a, b, c; printf ("Enter the number a:"); scanf ("% d", & a); printf ("Enter the number b"); scanf ("% d", & b); printf ("Addition:% d% d =% d cong \ n", a, b, a + b); printf ("subtraction:% d% d =% d Stay \ n", a, b, ab); printf ("Multiplication:% d% d face =% d \ n", a, b, a * b); printf ("phap share:% d% d =% d split \ n", a, b, a / b); return 0; }
Lesson 4: Write a program manolo in the sphere radius, calculate manolo and print out the area, th In order that the volume of a sphere. Guidelines: S = 4πR 2 and V = (4/3) πR 3. int main () {float r, S, V; printf ("click of radius r:"); scanf ("% manolo f", & r); S = 4 * r * r * 3:14; V = (4/3) * 3.14 * r * r * r; printf ("area of the sphere is:% .2f. \ n", s); printf ("The volume of the sphere is:% .2f. \ n", V); return manolo 0; }
Lesson 5: Write a program in any one of a print and squared value (a 2), cube (a third) of a value and a 4. Note: this section manolo you must add #include manolo <math.h> to use the function pow! int main () {double a; printf ("the values to a:"); manolo scanf ("% f", & a); printf ("a ^ 2 =% f \ n", pow (a, 2)); printf ("a ^ 3 =% f \ n", pow (a, 3)); printf ("a ^ 4 =% f \ n", pow (a, 4)); return 0; }
Lesson manolo 6: Write a program that reads from the keyboard 3 integer representation day, month, year and appears on-screen as a "right / month / year" (just take the last two numbers of the year). int main () {int day, month, male; printf ("right click"); scanf ("% d", manolo & right); printf ("Enter in the elevator:"); scanf ("% d ', & scale); printf ("The Click Five"); scanf ("% d", & male); printf manolo ("%. 2d /%. 2d /%. 2d \ n", right, scale, 100% male); manolo return 0; }
Last 7. Write a program in seconds, from 0 to 86 399, change the number of seconds into the format "HH: mm: ss", each component is a 2-digit integer. int main () {int Shine; printf ("Enter the number Shine"); scanf ("% d", & Shine); manolo if (Shine> 86399) {printf ("Enter the smaller \ n"); manolo return manolo 0; } Int = gio Shine / 3600; int = Minute Shine / 60 - gio * 60; Shine Shine = - * 60 mins - gio * 3600; printf ("%. 2d:%. 2d:%. 2d", hour, minute, seconds); return 0; }
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REMEDY SOME EXERCISE OF STYLE CHAIN 1.Dem how many spaces in the string. 2. Enter into a string, r

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REMEDY SOME EXERCISE OF STYLE CHAIN 1.Dem how many spaces in the string. 2. Enter into a string, remove the extra spaces in the string. 3. Click the two strings s1 and s2, s2 into s1 string concatenation. the watch hut Export string s1 screen 4.Doi all characters in the string to lowercase the watch hut (strlwr function is not used). 5.Doi all characters in the string to uppercase (struppr function is not used). 6.Viet program change the first letter of each word to uppercase. 7.Viet exchange programs alternating 1 uppercase letters and lowercase 1. Example: enter ABCDEFGH ABCDEFGH 8.Viet program changed the characters in reverse the watch hut sequence. For example, type ABCDE, the screen output is: EDCBA 9.Viet search program first character in the string is not whether, if the output from the position of the characters the watch hut rather then. (Eg a string the watch hut is "ho chi minh": type 'm' => 3 results) 10.Viet 1 program count characters appear many times in the series. (Eg, enter a string is "ho chi minh ", enter 'i' => KQ: 2) s1 and s2 11.Nhap chain, said the location of the string s2 occurs in s1. 12.Viet search program name in the string name. If so, then the output is the name entered correctly, the reverse notification is entered wrong. 13.Viet the island's position from the beginning and the end. For example, type "co bo an" output "security co bo" 14.Viet the watch hut cut function name string to string and string them lining name. For example, the string name is: "Nguyen Van A" cut off their second string is the string the watch hut underwear: "nguyenvan" chain named "A" 15.Nhap any string, then ask the user to split begins Where onward chain. Example: Enter the string the watch hut S1: "The University of Ton Duc Thang". The separation begins enter want the word "Religion" will output the string "Ton Duc Thang" screen 16.Viet check function string symmetric the watch hut or not ?. 17.Viet investigate the function of chain letters or numbers if there is split into a number the watch hut of separate array. 18.Nhap a string any, required the watch hut to enter one character you want to delete. Perform delete all characters in the string. 19.Doi the words in the first sentence to uppercase and not from the first sentence to lowercase. Example: Originally Posted a change the watch hut to: Nguyen Van A program 20.Viet reverse the order of the words in the string Example: Enter: c programming language 21.Xuat screen is: c slumber state s 22.Cho lap string str, enter the location and number vt to delete n characters, please delete n characters from the position in the string str vt. 23Nhap in string the watch hut str, string to insert and where to insert strInsert vt. Please insert string to string str strInser in position vt. 23.Cho a string, enter a word, write the program, delete it from the string has to. 24.Viet search bots see output drives a lot of characters the watch hut in the string. 1 25.Nhap any string, list view each character appears several the watch hut times.
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C provides a lot of string handling functions and all are located in the library string.h before us

C provides a lot of string handling functions and all are located in the library string.h before use must be declared with the keyword #include. parx racing The common functions are commonly used: strlen Syntax: unsigned int strlen (const char * str); Function: Returns the length of the string. The length of the string is determined by the null character parx racing should not be confused with the length of the array of characters. For example: char str [100] = "abcd"; Strlen (str) returns 4, while sizeof (str) returns 100. Code C: // strlen parx racing Example #include <stdio.h> #include <string.h> parx racing void main () {char str [100]; parx racing printf ("Enter a string:"); gets (str); printf ("The length of the string:% d", strlen (str)); } Strcpy Syntax: char * strcpy (char * destination, const char * source); Function: Copy the source string into the destination parx racing string and returns the destination string. Note destination string size must be equal to or greater than the source string and no value. Code C: // Example of strcpy function #include <stdio.h> #include <string.h> void main () {char a [100], parx racing b [100], c [100] = "abcdefg"; strcpy (a, c); strcpy (b, "12345"); printf ("a:% s \ nb:% s \ nc:% s \ n", a, b, c); } The result: parx racing a: b abcdefg: 12345 c: abcdefg strncpy Syntax: char * strncpy (char * destination, const char * source, unsigned int num); Function: Copy the source string into the destination string num number of the first character in the source string and returns the destination string. In case the number of characters to copy larger than the length of the source string the deficit will be filled with null characters. Code C: // Example parx racing of strncpy function #include <stdio.h> #include <string.h> void main () {char a [100], b [100], c [100] = "abcdefg"; strncpy (a, c, 3); strncpy parx racing (b, "12345", 7); printf ("a:% s \ nb:% s \ nc:% s \ n", a, b, c); } The result: a: b abc: 12345 c: abcdefg strcat Syntax: char * strcat (char * destination, const char * source); Function: Connect the source string into the destination string and returns the destination string. parx racing Null character of the destination string will be overwritten by the first character of the source string. Code C: // Example of strcat function #include <stdio.h> #include <string.h> void main () {char a [100]; strcat (a, "We"); strcat (a, "are"); strcat (a "programmer"); puts (a); } Result: We are programmer! strncat Syntax: char * strncat parx racing (char * destination, const char * source, unsigned int num); Integrate number num characters from the source string into the destination string and returns the destination string. In case of connection of characters greater than the length of the source string, only the contents of the string are connected through. Code C: // Example of strncat function #include <stdio.h> parx racing #include <string.h> void main () {char a [100]; strcat (a, "We Are The World!", 6); puts (a); } Result: We Are strcmp Syntax: int strcmp (const char * str1, const char * str2); Function: Compare two strings, returns -1 if str1 <str2, returns 0 if the two strings are equal, returns 1 if str1> str2. Principles Comparison: Compare each pair of characters from the beginning to the end of ASCII, in the first place different character string containing the smaller will be smaller, if different, the shorter string is smaller than the Code C: // Example of strcmp function parx racing #include <stdio.h> #include <string.h> void main () {char a [8] = "abcdefg", b [5] = "abcd"; int c = strcmp (a, b); if (c == -1) printf ("a <b"); else if (c == 0) printf ("a = b"); else printf ("a> b"); } The result: a <b Because D is less than d ASCII string containing it should be smaller. strlwr Syntax: char * strlwr (char * str); Function: In generally all uppercase characters in the series. Code C: // Example of a function strlwr #include <stdio.h> #include <string.h> void main () {char a [8] = "abcdefg"; printf ("% parx racing s", strlwr (a)); } Result: abcdefg strupr Syntax: char * strupr (char * str); Functions: Print flowers all lowercase characters in the series. Code C: // Example of a function strupr #include <stdio.h> #include <string.h> void main () {char a [8] = "abcdefg"; printf ("% s", strupr (a)); } Result: ABCDEFG
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If this is your first visit C Vietnamese community forum, please learn the rules involved, read the instructions before you register for an account. You have to register first, or sign in with your Facebook account you can send messages, download attachments. marware
I am learning C programming manager for all students. When you create jaw enter student information section is to enter your name spaces, then the error, no spaces are running normally Everyone just me fix this with
Code: #include <stdio.h> #include <string.h> typedef struct {char tenmon [50]; mamon char [50]; sotc int; float diem; } MH; typedef struct {char hoten [50]; student ID char [10]; int years; somon int; MH KQ [100]; int tongtc, tongtctl; dtbc float, Accumulated point; } SV; void nhapsv (SV & s) {printf ("Enter the student ID number:"); scanf ("% s", & s.mssv); printf ("full name"); scanf ("% s", & s.hoten); // Bi Error importing spaces printf ("Age"); scanf ("% d", & s.tuoi); printf ("Enter the mon:"); scanf ("% d", & s.somon); printf ("********************************** \ n"); for (int i = 0; i <s.somon; i ++) {printf ("Enter the name mon collection% d", i + 1); scanf ("% s", & s.kq [i] .tenmon); printf ("% d Enter the code mon collection", i + 1); scanf ("% s", & s.kq [i] .mamon); printf ("Enter the tc mon collection% d", i + 1); scanf ("% d", & s.kq [i] .sotc); printf ("% d Import diem collection mon", i + 1); scanf ("% f", & s.kq [i] .diem); } Printf ("********************************** \ n"); } Void main () {SV a; nhapsv (a); }
fgets (s. hoten, 50, stdin);
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T-v operating a sure knowledge! :(

T-v operating a sure knowledge! :(
Using basename okay.neu also need more information, astley clarke use the DC pathinfo will take the extension and not a file folder
basename ($ path)
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Already 13 years ago that the first part was released in theaters and received two continuing. At last, the fourth episode was also the big screen, and as the poster proclaimed best left to the last bite.
In 1999, we lived in a completely different world yet. In other partying young people, they dressed differently, behave misses dressy differently. In fact, it was completely different then the threshold of people as well as the title scene of the American pie cut in many places it in a certain security, however, the young people worshiped Jimbo (Jason Biggs), Oz (Chris Klein), Kevin (Thomas Ian Nicholas), Finch (Eddie Kaye Thomas) and Stifler (Seann William Scott), history, and a party girl who just wanted to be who they wanted to live their lives freely.
The sequel is again built on the same schema, of course, other jokes thrown in, but once again the old, familiar and well-liked characters. The third episode has komolyodott the topic, some of the actors misses dressy are written only to continue falling, now the jokes were less successful. It was not bad, but it was not the real thing. Of course, after this episode, the one-time moviegoers felötlik the question of whether it is the fourth American Pie is a flat, boring, gnawed bones? Well, you need to reassure everyone: no. The best part is meeting the previous one, worthy of continued and perhaps misses dressy worthy of closure.
As always refer to the fourth part of the meeting, but many people have their convinced that this is the percentage of that ...? Eighth pie? Well, this is not so. After the first and second misses dressy parts of the American pie the wedding came in the third section, and then presented the film were not true sequels. All items are only covered a similar theme, but none of them went to the original story, the original cast. So far as the American misses dressy meeting, 13 years after the first part takes place (in the movie and in real life as well), Jim and Michelle misses dressy (Alyson Hannigan) father and mother roles like approaching, Ostreicher became famous television Kevin sample husband, Finch, an adventurer, Stifler only Stifler left who trainee days in a company, but the biggest party night of the face ... you want to be.
... 15 answers joshfeed comment:
Jokes? Uhh ... Story? :: Are you f * cking kidding me? :: I grew up in a generation where the first part of a campaign of conquest continued. Have you never loved me or the Naked Gun comedies Airplane type real (real actors) they get better. Sorry. response on April 8, 2012 15:19
10 20 nico9519 Admiral misses dressy Adama (8/10)
Who was ajnálozta? Smooth jerk divide 'is misses dressy done, the gay bar has won at least the képkeretmájszter I already watched the movie because of the good humor to the story, although it is true that without Stifler would have been all over. response on April 7, 2012 21:22
I compare the 90'-years and years, and the current misses dressy style trends, etc. etc. are all musically dressing mind1 could go on ..... if you can not imagine what I akk this is ... I do not go if you do not mind because it could chew gum morning .. hm ... this is about .... am I meant that, for example, Bud Spencer and Hill film ... of course, today's generation, there are a lot of people who know and love does not conquer but to tell the truth than I was and I obviously did not watch it now than I was in what ..... I hope you understand that I thought maybe I was not the best example but the point is in it for you if you do not then it is not akk. response on April 7, 2012 19:08

The guy who hangs out without the Dying Light as weapons
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Since 2006, participating in different races sad Edina race car driver, but still be able to renew

The F1-live.hu broche could count on the high costs of the first engine in which the introduction broche of the 2014 resources in a row trigger a domino that really ledönthet everything. Renault, Mercedes broche and Ferrari broche are also high costs of introducing new engines, broche which put it mildly, does not bode well for the next year.
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Depending on the engine of the 2014 annual costs regarding an amount of 20-23 million package can be reported at Renault, while the same for Mercedes EUR 17 million. Ferrari offers the cheapest package of 15 million euros of its own. Many teams therefore be a hopeless situation.
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Even Lotus does not exclude the possibility of change, after the British nor the French renewed. The rumors that Ferrari and Honda will soon return could be considered in the future. Next article
Race Calendar broche (2014) first free practice session on March 13, Friday March 13 9:00 second free practice session on Friday 14 March 13:00 third free practice session on Saturday 09:00 qualifying session on March 14, Saturday March 15 Race 13:00 Sunday 06:00
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Constantly updated 16:16 serious progress in Lotusnál: It will be good for E23? 15:06 Yellow may Haas F1 car, serious professionals attached to the team this besírsz 14:16! ***** This is good! 13:47 Interview sad Edina: A Hungarian woman competitor 13:46 Lotus may surprise many people, says Grosjean 13:17 This year will be tough for Honda foolish changed the electronics component hole 12:16 Alonso believes McLaren-Honda's success, therefore, Needless to motivate the team 10:32 Red Bull Ferrari beats much time round, but unreliable 10:02 Yet escapes Marussia ?! 09:35 Now it's over? Hamilton and Scherzinger broke again
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The Friday demonstrations in Misurata militia headquarters of the outbreak lasted shootout and subs

Featured News Rosia Montana - The project opponents believed Iohannis resolution contradicts the previous statement of Listen! Tax deadlines approaching Győzike injured in a car accident on the tracks stopped the car at Kisvárda Together Baráthegyi trainers
Led to a state of emergency on Sunday in Tripoli 48 hours of general national congress (parliament) senior rebel militia formed from his staff in order to stop the bloodshed.
The Friday demonstrations in Misurata militia headquarters of the outbreak lasted shootout and subsequent clashes 45 people were killed prom hairstyles 2012 and 460 wounded in the Libyan capital, but doctors say the actual number of victims is probably much higher.
The public and private sector employees also participate in the strike, which will be held in the funeral of the victims and family solidarity - announced the Tripoli City Council (Mayor's Office) communication.
Ukrainian doctors working in the city on Saturday, after the relative calm dawn on Sunday was intensified again in the shootout between the former rebel militias. The urban area of more complete streets were closed for security reasons.
On Saturday, it became known that the Misurata militants seized a military base in a suburb of Tripoli, prom hairstyles 2012 looted the armory, and Miszrátába delivered every weapon found there.
The Tripoli regularly protest against all kinds üzelmekkel, kidnapping, torture and secret prisons maintaining prom hairstyles 2012 accused militants from other regions who came to fight against Muammar Gaddafi's regime to the capital in August 2011, and has never left.
The Libyan capital prom hairstyles 2012 on Friday mérgesedett the situation prom hairstyles 2012 where Gargúr city district of Misurata militia demanded the departure of the militants fired at peaceful demonstrators. Then, angry and stormed Tripoli militia set fire to the headquarters. prom hairstyles 2012 The shooting continued on Saturday.
On Saturday, several hundred people gathered in the city center, in the Martyrs to take a final farewell to the victims are killed the previous day. Dozens of young milíciaellenes chanted slogans and demanded the re-establishment of the army. "I do not Gaddafi's soldiers fired on the demonstrators so cruel" prom hairstyles 2012 - one of the participants said indignantly.
19 days ago
Would aircraft was claimed their passengers to be able to get up 11/28/2014
Rosia Montana - The project opponents believed Iohannis resolution contradicts the previous statement of Watch out! Tax deadlines approaching Győzike injured in a car accident on the tracks stopped the car at Kisvárda Together Baráthegyi trainers
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Afternoon has been estimated between 200 thousand and 700 thousand the number of demonstrators. In

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Afternoon has been estimated between 200 thousand and 700 thousand the number of demonstrators. In front of the presidential office choice clothing building, the situation became tense after unknown - of whom did not know that protesters or provocateurs - bulldozer tried to break through choice clothing the police cordon. choice clothing The riot police and könnygáz- hanggránátokat was used against the invaders, who in response to fireworks, rockets, messengers, throwing sticks to the law enforcers. Notification of the Ministry of the Interior, more than a few hundred policemen and injured choice clothing attacker. The presidential office entrance road to the metal barriers and police blocked with buses. The presidential office protesters were divided into two groups: choice clothing one group tried to divert the river bed peaceful protest, and the protection provided by the police, on the other hand was impressive attacking again and again.
The opposition leaders, choice clothing challengers stoked tensions between the demonstrators and law enforcement staff of the presidential office. Vitali choice clothing Klitschko has urged the demonstrators not to yield to the provocation.
Arseny Jacenyuk behind, the jailed former prime minister Yulia Tymoshenko's Motherland Party faction leader in the field of protesters in front of Independence choice clothing stated choice clothing that national resistance created choice clothing by the opposition headquarters in Kiev, which will coordinate the demonstrations.
Oleh Tyahnyibok, the nationalist Freedom (Svoboda) warned the president of discipline Independence teréről sites for migratory demonstrators, asking them not to act against the organizers of the protest's instructions. "Revolution!" Exclamation concluded his speech, which was further along with the crowd chanted.
Opposition leaders called for a general strike choice clothing across the country, President Viktor Yanukovych and resign. Personally, it is considered to be responsible for not created the Association Agreement between Ukraine and the EU this week in Vilnius, the EU Eastern Partnership summit. They broke the Kiev city hall
During the day, a group of protesters invaded the capital city governing administration building and took the first level. The town house was a lot of intruders, masked man, who the nationalist Freedom (Svoboda) party activists. Should explain that the premise that the demonstrators megmelegedhessenek. Unions near the office of President House is occupied by a group of protesters, mostly pro-freedom activists also.
Sunday in the country were also pro-EU movements, even in the mainly Russian-speaking and pro-Yanukovych populated cities such as Donetsk, Eastern Ukraine and Odessa in the south of the country, and also Simferopol. choice clothing
The growing crowd moves event trigger was when Saturday dawn of Independence Square hundreds of people - mostly choice clothing university choice clothing students - demonstrating crowd batons beat and kicked riot police, choice clothing witnesses said that for them, who tried to escape and no resistance can be certified against the tömegoszlatással.
In Kiev ambulance service chief physician according to 35 of the demonstrators choice clothing sought medical help, seven of them pushed hospitalization. The Interior Ministry said 12 policemen were injured in the central square. The authorities had arrested 35 protesters, but they were released the same day. The Kiev police explained the dawn riot-control to prevent the demonstration in the capital structure of the new year fenyőfája támasztószerkezetének.
"I deeply felháborítanak the events that occurred the night of the Liberty Square. I condemn the actions that led to stapling and the suffering of the people ", - Yanukovych wrote, I promised choice clothing that you are responsible choice clothing for what happened will be punished. Yanukovych, however, the release did not name the police as responsible for the violence.
Valery Korin Kiev police chief said the riot police at dawn on Saturday when the crowd control "excessive force" deployed against anti-government protesters, so the American hírtévé CNN, referring to the Ukrainian police choice clothing communication stated that the police chief resigned.
20:25 Chainsaw and carrying a firearm, he wanted to talk with the president
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